## Description

1 [40 points] Some Projective Geometry Problems

Suppose there are two parallel lines that extend to infinity in our world coordinates. The images of these

two lines intersect at a point, v, on the image plane known as the vanishing point. In this problem we choose

to represent the lines as

l =

r

cos α

cos β

cos γ

r ∈ R

where α, β, γ are the angles from the x, y and z world axes respectively.

(a) [10 points] Using homogeneous coordinates to show that the image coordinates of the vanishing point

v

can be written as v = KRd , where

d =

cos α

cos β

cos γ

K is the camera calibration matrix and R is the rotation matrix between the camera and the world

coordinates.

(b) [15 points] Express the line direction d in terms of K, R and v.

Remark: Any matrix inverses which do not hold in general, must be shown to hold in this case.

(c) [15 points] Now consider the situation where three lines intersect such that each line is orthogonal to

the other two. That is, each line’s directional vector d satisfies the following.

dT

1 d2 = 0 dT

1 d3 = 0 dT

2 d3 = 0

Using this property, show that

(K−1vi)

T (K−1vj ) = 0

for i = j.

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2 [60 points] Affine Camera Calibration

It was shown in the class that a perspective camera can be modeled using a 3 × 4 matrix:

x

y

w

=

p11 p12 p13 p14

p21 p22 p23 p24

p31 p32 p33 p34

X

Y

Z

1

(1)

which means that the image at point (X, Y, Z) in the scene has pixel coordinates (x/w, y/w). The 3 × 4

matrix can be factorized into intrinsic and extrinsic parameters.

An affine camera is a special case of this model in which rays joining a point in the scene to its projection

on the image plane are parallel. Examples of affine cameras include orthographic projection and weakly

perspective projection. An affine camera can be modeled as:

x

y

1

=

p11 p12 p13 p14

p21 p22 p23 p24

0 0 0 1

X

Y

Z

1

(2)

which gives the relation between a scene point (X, Y, Z) and its image (x, y). The difference is that the

bottom row of the matrix is [ 0 0 0 1 ], so there are fewer parameters we need to calibrate. More

importantly, there is no division required (the homogeneous coordinate is 1) which means this is a linear

mode. This makes the affine model much simpler to work with mathematically at the cost of losing some

accuracy. The affine model is used as an approximation of the perspective model when the loss of accuracy

can be tolerated, or to reduce the number of parameters being modeled.

Calibration of an affine camera involves estimating the 8 unknown entries of the matrix in Eq. 2. (This

matrix can also be factorized into intrinsics and extrinsics, but that is outside the scope of this homework).

Factorization is accomplished by having the camera observe a calibration pattern with easy-to-detect corners.

Scene Coordinate System

The calibration pattern used is shown in Fig. 2, which is a 6 × 6 grid of squares. Each square is 17.5mm ×

17.5mm. The separation between adjacent squares too is 17.5mm, so the entire grid is 192.5mm×192.5mm.

For calibration, images of the pattern at 2 different positions were captured. These images are shown in

Fig. 2 and are also present in the assignment folder. For the second image, the calibration pattern has been

moved back (along its normal) from the rest position by 9.5mm.

We will choose the origin of our 3D coordinate system to be the top left corner of the calibration pattern

in the rest position. The X-axis runs left to right parallel to the rows of squares. The Y -axis runs top to

bottom parallel to the column of squares. We will work in units of millimeters. All the square corners from

the first position corresponds to Z = 0. The second position of the calibration grid corresponds to Z = 9.5.

The top left corner in the first image has 3D scene coordinates (0, 0, 0) and the bottom right corner in the

second image has 3D scene coordinates (192.5, 192.5, 9.5). This scene coordinate system is labeled in Fig. 2.

Corner Extraction

The task that you must complete for this question begins here. Extract the feature correspondences required

for calibration. In other words, first find the scene coordinates of the square corners of the calibration grid.

Next, find the corresponding pixel coordinates in the images.

If you wish to measure the pixel coordinates interactively in MATLAB, you may find the function ginput

useful. It is strongly recommended that you save this matrix of measurements in a files for later use. You

do not need to find all the corners, but the more corners you use the more accurate the calibration is likely

to be. Be sure to include corners for both images. We recommend using at least 12 corners from each image.

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(a) Image formation in an affine camera. Points are projected via parallel rays onto the image plane

(b) Image of calibration grid at Z = 0 (c) Image of calibration grid at Z = 9.5

Figure 2: Affine camera: image formation and calibration images

Solving for the camera matrix

Having measured enough features, we can now solve for the camera parameters using Eq. 2. Note that

each measurements (xi

, yi) ↔ (Xi

, Yi

, Zi) yields two linear equations for the 8 unknown camera parameters.

Given N corner measurements, we have 2N equations and 8 unknowns. Using your measured feature

correspondences as input, write code which constructs the linear system of equations and solves for the

camera parameters which minimizes the least-squares error.

(a) [10 points] Could you calibrate the matrix with only one checkerboard image? Explain Why.

(b) [25 points] The RMS error (in pixels) between the corner positions and the positions predicted by the

camera parameters.

(c) [25 points] Give your 3 × 4 calibrated camera matrix.

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