CS575 Homework 2 solution

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1. You are given an input array of integers: [8, 3, 7, 1, 2, 10, 5].
(a) [4 points] Build a max-heap for the input data. (No credit will be given for a min-heap.)
Draw figures to show the process.
(b) [6 points] Using the max-heap built above, sort the input data in non-ascending order
using the heap sort algorithm. Draw figures to show every step.
2. Assume that you are given an array of n elements sorted in non-descending order where n ≥ 1.
Given the assumption, solve the following problem via divide and conquer.
(a) [10 points] Design a ternary search algorithm that searches the array by dividing it into
three subarrarys where each sublist has approximately n/3 data elements. Write a pseudo
code to do ternary search with the worst case time complexity of Θ(log3 n). (Hint: Extend
the binary search algorithm.)
(b) [10 points] Prove that the worst case time complexity of your algorithm is Θ(log3 n).
Write recursive equations and solve them iteratively. (Don’t use the master theorem).
3. Use the radix sort algorithm to sort the following list of numbers in non-descending order:
321, 38, 15, 3, 9, 82, 10, 11.
(a) Draw three figures (one for each digit) to show the process step by step [5 points].
(b) Repeat part (a) by sorting the most significant digit first. Does it sort the numbers
properly? Show the process. [5 points].
4. Prove that the lower bound of sorting based on comparions is Ω(nlgn) [10 points].
5. The worst case time complexity of quick sort is O(n
2
). Regarding this, answer the following
questions.
(a) Briefly describe when the time complexity of quick sort becomes O(n
2
) [2 points].
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(b) Write recursive equations for the worst case and solve them to prove that the time complexity is O(n
2
) [6 points].
(c) Briefly describe how to avoid the worst case in quick sort [2 points].
6. Is it a good idea to apply the divide and conquer method to compute a Fobonacci number?
(a) Simply say yes or no [1 point].
(b) Justify your yes/no answer [9 points].
7. Prove the following.
(a) [10 points] n
k = o(2k
).
(b) [10 points] lgn = o(n).
(c) [10 points] n = o(n
3
).
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