CPSC323 Assignment 3 solution

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Assignment 3 consists of : 1) Documentation and Specifications for you project (10%) 2) Symbol table handling and Type Checking or Parse Tree internal representation (20%) 3) Generating intermediate code for the simplified version of our Grammar from assignment2. Or implement a Bottom-Up approach for the Syntax Analyzer. Or add implementation to your Top-Down RDP approach. Or implementing your Top-Down Syntax Analyzer using the Stack. Or use a different approach than the one you used for the last project. More points for: Scope Checking, Type Checking, Testing, Error Handling, and/or integrating all the assignments to work together. The more that is implemented additionally, the more points you will get. Our Grammar: • The grammar is essentially the same in class except that it is more simplified and it has NO • No “real” type is allowed Some Semantics: • Consider that “true” has an integer value of 1 and “false” has an integer value of 0. • No arithmetic operations are allowed for booleans. • The types must match for arithmetic operations (no conversions) Part 1) Documentation and Specifications (10%): Document your project and explain your approach and functions and/or class using the documentation template. Include program flow and diagrams for maximum points. Part 2) Symbol table Handling or Parse Tree internal representation (20%): Every identifier declared in the program should be placed in a symbol table and accessed by the symbol table handling procedures. a) Each entry in the symbol table should hold the lexeme, and a “memory address” where an identifier is placed within the symbol table. For example, define a global integer variable called “Memory_address” and set initially 5000 and increment it by one when a new identifier is declared and placed into the table. b) You need to write a procedure that will check to see if a particular identifier is already in the 2 table, a procedure that will insert into the table and a procedure that will printout all identifiers in the table. If an identifier is used without declaring it, then the parser should provide an error message. Also, if an identifier is already in the table and wants to declare it for the second time, then the parser should provide an error message. Also, you should check the type match. Part 3) Generating the assembly code or the other options above (70%): Modify your parser according to the Grammar from class so that your parser will produce the assembly code instructions. The instructions should be kept in an array and at the end, the content of the array is printed out to produce the listing of assembly code. Your array should hold at least 1000 assembly instructions. The instruction starts from 1. The listing should include an array index for each entry so that it serves as label to jump to. The compiler should also produce a listing of all the identifiers. Our target machine is a virtual machine based on a stack with the following instructions PUSHI {Integer Value} Pushes the {Integer Value} onto the Top of the Stack (TOS) PUSHM {ML – Memory Location} Pushes the value stored at {ML} onto TOS POPM {ML} Pops the value from the top of the stack and stores it at {ML} STDOUT Pops the value from TOS and outputs it to the standard output STDIN Get the value from the standard input and place in onto the TOS ADD Pop the first two items from stack and push the sum onto the TOS SUB Pop the first two items from stack and push the difference onto the TOS ( Second item – First item) MUL Pop the first two items from stack and push the product onto the TOS DIV Pop the first two items from stack and push the result onto the TOS ( Second item / First item and ignore the remainder) GRT Pops two items from the stack and pushes 1 onto TOS if second item is larger otherwise push 0 LES Pops two items from the stack and pushes 1 onto TOS if the second item is smaller than first item otherwise push 0 EQU Pops two items from the stack and pushes 1 onto TOS if they are equal otherwise push 0 NEQ Pops two items from the stack and pushes 1 onto TOS if they are not equal otherwise push 0 GEQ Pops two items from the stack and pushes 1 onto TOS if second item is larger or equal, otherwise push 0 LEQ Pops two items from the stack and pushes 1 onto TOS if second item is less or equal, otherwise push 0 JUMPZ {IL – Instruction Location} Pop the stack and if the value is 0 then jump to {IL} JUMP {IL} Unconditionally jump to {IL} LABEL Empty Instruction; Provides the instruction location to jump to. 3 A Sample Source Code ! this is comment for this sample code for assignment 3 ! int i, max, sum; sum = 0; i = 1; input ( max); while (i < max) { sum = sum + i; i = i + 1; } output (sum + max); One Possible Assembly Code Listing 1 PUSHI 0 2 POPM 5002 3 PUSHI 1 4 POPM 5000 5 STDIN 6 POPM 5001 7 LABEL 8 PUSHM 5000 9 PUSHM 5001 10 LES 11 JUMPZ 21 12 PUSHM 5002 13 PUSHM 5000 14 ADD 15 POPM 5002 17 PUSHM 5000 17 PUSHI 1 18 ADD 19 POPM 5000 20 JUMP 7 21 PUSHM 5002 22 PUSHM 5001 23 ADD 24 STDOUT 4 Symbol Table Identifier MemoryLocation Type i 5000 integer max 5001 integer sum 5002 integer NOTE: – DO NOT CREATE YOUR OWN ASSEMBLY INSTRUCTIONS. USE ONLY PROVIDED INSTRUCTIONS. – Turn in your document according to the instructions given in the project outline.