COL106 Assignments 2 and 3 Mobile phone tracking system solved

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In these two assignments, we will design a data structure that will help us solve a simplified version of the mobile phone tracking problem, i.e., the fundamental problem of cellular networks: When a phone is called, find where it is located so that a connection may be established.
Mobile phone tracking system description
As we know each mobile phone that is switched on is connected to the base station which is nearest. These base stations are popularly called cell phone towers. Although sometimes we may be within range of more than one base station, each phone is registered to exactly one base station at any point of time. When the phone moves from the area of one base station to another, it will be de-registered at its current base station and re-registered at new base station.
Making a phone call. When a phone call is made from phone p1 registered with base station b1 to a phone p2, the first thing that the base station b1 has to do is to find the base station with which p2 is registered. For this purpose there is an elaborate technology framework that has been developed over time. You can read more about it on the Web. But, for now, we will assume that b1 sends a query to a central server C which maintains a data structure that can answer the query and return the name of the base station, let’s call it b2, with which p2 is registered. C will also send some routing information to b1 so that b1 can initiate a call with b2 and, through the base
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stations p1 and p2 can talk. It is the data structure at C that we will be implementing in this assignment.
A hierarchical call routing structure. We will assume that geography is partitioned in a hierarchical way. At the lowest level is the individual base station which defines an area around it such that all phones in that area are registered with it, e.g., all phones that are currently located in Bharti building, School of IT and IIT Hospital are registered with the base station in Jia Sarai. This base station also serves phone in Jia Sarai and maybe some phones on Outer Ring Road in front of Jia Sarai. Further we assume that base stations are grouped into geographical locations served by an level 1 area exchange. So, for example, the Jia Sarai base station may be served by the Hauz Khas level 1 area exchange. Each level i area exchange is served by a level i+1 area exchange which serves a number of level i area exchanges, e.g., the Hauz Khas level 1 area exchange and the Malviya level 1 area exchange may be both served by a South-Central Delhi level 2 area exchange. A base station can be considered to be a level 0 area exchange in this hierarchical structure. Given a level i exchange f, we say that the level i + 1 exchange that serves it is the parent of f, and denote this parent(f). We will call this hierarchical call routing structure the routing map of the mobile phone network.
Maintaining the location of mobile phones. Every level i area exchange, e, maintains a set of mobile phones, Se, as follows. The set Se is called the resident set of e. The level 0 area exchanges (base stations) maintain the set of mobile phones registered directly with them. A level i+1 area exchange e, maintains the set Se defined as follows se = [ parent(f)=e Sf,
i.e., the union of the sets of mobile phones maintained by all the level i area exchanges it serves. Clearly, the root of the routing map maintains the set of all currently registered mobile phones.
Tracking a mobile phone. The routing map along with the resident sets of each area exchange makes up the mobile phone tracking data structure we
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will be using. This data structure will be stored at the central server C. The process of tracking goes as follows. • When a base station b receives a call for a mobile phone with number m it sends this query to C. • If the root of the routing map is r, we first check if m ∈ Sr. If not then we tell b that the number m is “not reachable.” • If m ∈ Sr we find that e such that parent(e) = r and m ∈ Se, i.e. we find the child of r which contains m in its resident set. • Continue like this till we reach all the way down to a leaf of the routing map. This leaf is a base station b0. The central server sends b0 to b along with the path in the routing map from b to b0.
The programming assignments
We now describe the implementation details of the system defined above. This is split into two programming assignments, #2 and #3 with one extra credit problem. Please note that the assignments have two different deadlines.
Assignment 2 [100 marks] Deadline: 11:55 PM, 10 September 2016
• Write a java class called Myset that implements sets, with the following methods:
– public Boolean IsEmpty(): returns true if the set is empty. – public Boolean IsMember(Object o): Returns true if o is in the set, false otherwise. – public void Insert(Object o): Inserts o into the set. – public void Delete(Object o): Deletes o from the set, throws exception if o is not in the set. – public Myset Union(Myset a): Returns a set which is the union of the current set with the set a.
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– public Myset Intersection(Myset a): Returns a set which is the intersection of the current set with the set a. You may use a linked list of objects to implement the Myset class. Note that Object is the fundamental class in Java. You can cast it to any class that you want (Integer, Float, Double, etc). Demo instructions: Write your code for set in a file named Myset.java. Ensure that the name of the functions and the type of the function arguments/return type should be same as mentioned here. Implement the linked list yourself. You may copy the code for linked lists out of the book or any other source. Optional challenge problem: Bloom filters are an efficient data structure for implementing the class Myset. Look up Bloom filters on the web and write an alternate implementation of the Myset class which uses Bloom filters instead of linked lists. Keep in mind that the results of the IsMember() method in a Bloom filter implementation of a set have an error in them. How does this affect the working of the overall system? How can you account for this?
• Write a java class called MobilePhone, with the following methods: – MobilePhone(Int number): constructor to create a mobile phone. Unique identifier for a mobile phone is an integer. – public Int number(): returns the id of the mobile phone. – public Boolean status(): returns the status of the phone, i.e. switched on or switched off. – public void switchOn(): Changes the status to switched on. – public void switchOff(): Changes the status to switched off. – public Exchange location(): returns the base station with which the phone is registered if the phone is switched on and an exception if the phone is off. The class Exchange will be described next. • Create a class MobilePhoneSet which stores MobilePhone objects in a Myset.
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• Create a class ExchangeList which implements a linked list of exchanges. • Write a java class Exchange that will form the nodes of the routing map structure. The class should have the following methods.
– Exchange(Int number): constructor to create an exchange. Unique identifier for an exchange is an integer. – All usual Node methods for a general tree like public Exchange parent(), public Exchange numChildren() (for number of children), public Exchange child(int i) (returns the ith child), public Boolean isRoot(), public RoutingMapTree subtree(int i) (returns the ith subtree) and any other tree methods you need. The class definition RoutingMapTree will be defined later. – public MobilePhoneSet residentSet(): This returns the resident set of mobile phones of the exchange. • Write a java class RoutingMapTree which is a tree class whose nodes are from the Exchange class. The class should contain the following:
– RoutingMapTree(): constructor method. This should create a RoutingMapTree with one Exchange node, the root node which has an identifier of 0. Create other constructors that you deem necessary. – All general tree methods like public Boolean containsNode(Exchange a) but with Exchange as the node class. – public void switchOn(MobilePhone a, Exchange b): This method only works on mobile phones that are currently switched off. It switches the phone a on and registers it with base station b. The entire routing map tree will be updated accordingly. – public void switchOff(MobilePhone a): This method only works on mobile phones that are currently switched on. It switches the phone a off. The entire routing map tree has to be updated accordingly. – public void performAction(String actionMessage): This the main stub method that you have to implement. It takes an action as a string. The list of actions, and their format will be described next.
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Demo instructions: In this assignment, you are given files: assn2checker.java, RoutingMapTree.java and actions1.txt. assn2checker.java file is our program which reads the input actions from the actions1.txt file, and feeds them to RoutingMapTree.java. You have to create the file for other classes. Each class file should contain the methods that we have explicitly mentioned in the problem statement. You can implement other functions too if you want. The primary task of your assignment is to give the correct answer to the query messages (described later). We will verify the output of the program during the demo. Here is a list of action messages that you need to handle:
• addExchange a b This should create a new Exchange b, and add it to the child list of Exchange a. If node a has n children, b should be its (n+1)th child. If there is no Exchange with identifier a, then throw an Exception. • switchOnMobile a b This should switch ON the mobile phone a at Exchange b. If the mobile did not exist earlier, create a new mobile phone with identifier a. If there is no Exchange with an identifier b, throw an exception. • switchOffMobile a This should switch OFF the mobile phone a. If there is no mobile phone with identifier a, then throw an Exception. • queryNthChild a b This should print the identifier of the Exchange which is the (b)th child of Exchange a. • queryMobilePhoneSet a This should print the identifier of all the mobile phones which are part of the resident set of the Exchange with identifier a.
Points to note: • Your program’s response should be printed inside the performAction method of the RoutingMapTree class. Use the System.out.println() method to print the output. • If the code discovers that there is an inconsistent action being performed, instead of just exiting, you should print an error message, and continue with program execution. Example of an inconsistent action can be switching off a mobile that does not exist. It will be better
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if you handle such inconsistent states by raising suitable Exception in the implementing class (Set/Exchange), and handling it in the RoutingMapTree class. Read relevant text on the web to know more about raising and handling Exceptions. • We will be using a different actions.txt file in the demo. So make sure that your program considers all conditions before you submit it on Moodle. If you have formatting issues in using this file on Windows/MacOS platform, create a suitable version of the same file for your platform. By formatting, we mean the new-line/space/tab-space.
Assignment 3 [100 marks] Deadline: 11:55 PM, 21 September 2016
In this assignment we move on to implementing the details of the tracking system. Implement the following additional methods in the RoutingMapTree class.
• public Exchange findPhone(MobilePhone m): Given a mobile phone m it returns the level 0 area exchange with which it is registered or throws an exception if the phone is not found or switched off. • public Exchange lowestRouter(Exchange a, Exchange b): Given two level 0 area exchanges a and b this method returns the level i exchange with the smallest possible value of i which contains both a and b in its subtree. If a = b then the answer is a itself. • public ExchangeList routeCall(MobilePhone a, MobilePhone b): This method helps initiate a call from phone a to phone b. It returns a list of exchanges. This list starts from the base station where a is registered and ends at the base station where b is registered and represents the shortest route in the routing map tree between the two base stations. It goes up from the initiating base station all the way to the lowestRouter connecting the initiating base station to the final base station and then down again. The method throws exceptions as appropriate. • public void movePhone(MobilePhone a, Exchange b): This method modifies the routing map by changing the location of mobile phone a
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from its current location to the base station b. Note that b must be a base station and that this operation is only valid for mobile phones that are currently switched on.
Demo instructions: The evaluation framework for assignment 3 is same as assignment 2. We have added extra action messages to test the mobile tracking system. Here is a list of the extra action messages that your RoutingMapTree should support. • queryFindPhone a This should print the identifier of the exchange returned by the findPhone(MobilePhone m) method. Here, m represents the mobile phone whose identifier is a. • queryLowestRouter a b This should print the identifier of the exchange returned by the lowestRouter(Exchange e1, Exchange e2) method. Here, e1 and e2 represent exchanges with identifier a and b respectively. • queryFindCallPath a b This should print the list returned by the routeCall(MobilePhone m1, MobilePhone m2) method. Here, m1 and m2 represent mobile phones with identifier a and b respectively. Successive entries in the list should be separated by a comma. • movePhone a b This action should set the level 0 area exchange of the mobile phone with identifier a to exchange with identifier b. Throw exception if mobile a is not available, or exchange b does not exist.
Consider all possible scenarios for each action message. When an inconsistent action is triggered, your code should display suitable error message, and continue with the next action message. Note: Your program’s response should be printed inside the performAction method of the RoutingMapTree class. Use the System.out.println() method to print the output. For the given actions.txt file, we have provided a answers.txt file showing the expected format of the program response.
Assignment 2 and 3 Extra Credit [40 marks] Deadline: 11:55 PM, 10 September 2016 Submit along with Assignment 3
To make the whole system much closer to reality, write a multithreaded implementation for it. Do the following:
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• Create one thread for each mobile phone and one thread for the central server. • The central server thread will maintain the routing map tree. • Mobile phone thread will perform the actions in MobilePhone class i.e. each mobile phone thread
– is either in waiting mode, or it initiates a call, – changes status from on to off or vice versa, – moves from one base station to another (to do so it has to communicate with central server thread). • You can introduce a new kind of status field (busy) which is on when the phone is on an active call and off otherwise. When a call is initiated by a phone, your multithreaded implementation should send a message to the destination phone which can accept or reject the request based on its on/off/busy status. Once the call is accepted both the phones become busy.
Demo instructions: • You should incorporate the code written only for this part in a new file and submit it along with the zipped directory containing Assignment 3 code. The demo for the extra credit will be held along with the Assignment 3 demo. • There will be no checker file for this part. The input should be read from a file. The input format can be: T-start(%f) Opn(%s) T-end(%f)
where: T-start is the time at which the operation is requested, Opn is the operation to be performed at a given time. The third field T-end is the duration of a call and is valid only if the operation routeCall. It is the time for which the mobile phone is busy. After which the mobile phone should change its status. For other operations, this field can be set to be -1. • It is your responsibility to have input files ready at demo time.
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• You must provide an option that generates a random sequence of requests. Each phone that is idle should generate a random operation (call, on-off or vice versa, movement) after waiting for a random amount of time. The duration of a call request should also be randomly selected. In order to do this your mobile phone class should include a random option and each thread should randomly generate requests. The waiting time between requests should be random with an expected time of 5 seconds. Call durations should also be of the order of 4-5 seconds. • When your program starts it should ask the user whether she wants to read input from a file or operate in random mode. If the user asks for random mode then it should ask her for a time duration of the simulation. • Output should in the form of a dashboard that allows you to view the status of the system as it evolves. This dashboard doesn’t have to be very fancy but should list the position of the nodes and their current status. It should also inform the viewer of the requests being handled by the central server at any point in time (and when they are completed).